Question 1132367: Aidan is five times as old as Ethan, but in four years, he will be 8 years more than thrice as him. Find the age of each now. Found 3 solutions by MathLover1, MathTherapy, ikleyn:Answer by MathLover1(20850) (Show Source):
You can put this solution on YOUR website! , . Find the age of each now.
let Aidan’s age be and Ethan’s age be
given:
Aidan is five times as old as Ethan
......eq.1
but in four years, he will be 8 years more than thrice as him
......eq.2
substitute from eq.1
......solve for
go to
......eq.1..substitute
=> Aidan is years old and Ethan is years old now
You can put this solution on YOUR website! Aidan is five times as old as Ethan, but in four years, he will be 8 years more than thrice as him. Find the age of each now.
Let x be the Ethan's age; then 5x is the Aidan's age.
In 4 years
5x + 4 = 3*(x+4) +8
Simplify and solve
5x + 4 = 3x + 12 + 8
5x - 3x = 12 + 8 - 4
2x = 16
x = = 8.
Answer. Younger is 8 years old; elder is 5*8 = 40 years old.
