SOLUTION: Kiaria is 7 years older than Jay. Martha is twice as old as Kiaria. The sum of their three ages is 77. Find the ratio of Jay's age to Kiaria's age to martha's age.

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Kiaria is 7 years older than Jay. Martha is twice as old as Kiaria. The sum of their three ages is 77. Find the ratio of Jay's age to Kiaria's age to martha's age.       Log On

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Question 1129240: Kiaria is 7 years older than Jay.
Martha is twice as old as Kiaria.
The sum of their three ages is 77.
Find the ratio of Jay's age to Kiaria's age to martha's age.
Found 2 solutions by josmiceli, josgarithmetic:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+k+=+j+%2B+7+
+m+=+2k+
+k+%2B+j+%2B+m+=+77+
--------------------------
+j+=+k+-+7+
j : k : m = j : k : 2k
--------------------------
+k+%2B+k+-+7+%2B+2k+=+77+
+4k+=+84+
+k+=+21+
and
+j+=+k+-+7++
+j+=+21+-+7+
+j+=+14+
So, +j+=+%282%2F3%29%2Ak+
---------------------------
j : k : m = (2/3)*k : k : 2k
j : k : m = 2k : 3k : 6k

Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
Kiaria      j+7
Jay          j
Martha      2(j+7)
SUM           77

%28j%2B7%29%2Bj%2B2%28j%2B7%29=77
-
j%2B7%2Bj%2B2j%2B14=77
4j%2B21=77
4j=77-21
4j=56
4j=8%2A7=2%2A4%2A7
j=14 
Kiaria       21
Jay          14
Martha       42
SUM           77


Ratio k : j : m

          21 : 14 : 42

        ----------------- 
        |   3 : 2  : 6   |
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