Question 1126842: Moe is twice as old as Larry. Moe is five years older than curly. Together Moe, Curly and Larry's ages add up to 65. how old are they? Found 3 solutions by FrankM, josgarithmetic, MathTherapy:Answer by FrankM(1040) (Show Source):
You can put this solution on YOUR website! M=2L
M=C+5
M+C+L=65
Combine 1st 2 eq
2L=C+5, or L= 1/2(C+5)
(C+5)+C+1/2(C+5)=65
2C+10+2C+C+5=130
5C+15=130
5C=115
C=23 M=28 L=14
You can put this solution on YOUR website!
Moe is twice as old as Larry. Moe is five years older than curly. Together Moe, Curly and Larry's ages add up to 65. how old are they?
Let Larry's age be L:
Then Moe's is 2L
Moe, or 2L = C + 5
C, or Curly is: 2L - 5
We then get: L + 2L + 2L - 5 = 65
5L = 70
L, or Larry is:
You should be able to find Moe's and Curly's ages now.