Question 1120629: Ten year ago, John was half of Michael's age. If the ratio of their present ages is 3:4. What will be their total of the present ages?
Answer by greenestamps(13200)   (Show Source):
You can put this solution on YOUR website!
(1) The ratio of their current ages is 3:4, so let John's age be 3x and Michael's age be 4x.
It is a typical way to start work on a problem where a ratio is given.
(2) Using 3x and 4x for their current ages, write expressions for their ages 10 years ago.
(3) Write and solve the equation for x that says John's age 10 years ago was half of Michael's age then.
(4) Use the value you find for x to find their current ages, which are 3x and 4x.
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