.
D is 2 years younger than J. The difference between the squares of their ages is 28. how old is each
~~~~~~~~~~~~~~~~~~~~~
See what is RIGHT WAY solving such problems.
You are given these two equations
J - D = 2 (1)
-
= 28 (2)
From (2), you have
(J-D)*(J+D) = 28 (2')
In (2') replace (J-D) by 2, since it is given. You have
2*(J+D) = 28, which implies
J + D = 14. (3)
Now you have these two equations
J - D = 2 which is the same as (1), and
J + D = 14 which is (3).
Now add these equations . Yuo will get
2J = 2 + 14 = 16, which implies J =
= 8.
Then D = 8-2 = 6.
Answer. J is 8. D is 6
Solved.