Question 1112494: The present age of a women is 4 times as her daughter's age. When the women was 29 years old, her only son, who is two years younger than her only daughter, was born. What is the present age of the son?
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52802)   (Show Source):
You can put this solution on YOUR website! .
The translation to the Math language is THIS:
W = 4D (1) ("The present age of a women (W) is 4 times as her daughter's age (D)")
W = S + 29 (2) ("The women is 29 years older than the son (S)")
D = S + 2 (3) ("The difference between the daughter and the son is 2 years")
Then the difference between the women and the daughter is 27 years,
so W = 4*(W-27) ====> W = 4W - 108 ====> 3W = 108 ====> W =  = 36.
Answer. The women is 36 years old; the daughter is 36/4 = 9 years old and the son is 7 years old.
Check. When the women was 29 years, i.e. 7 years ago, the daughter was 9-7 = 2 years old,
and these 2 years is/are the difference between the daughter and the son.
! Correct !
Solved.
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Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website! The present age of a women is 4 times as her daughter's age. When the women was 29 years old, her only son, who is two years younger than her only daughter, was born. What is the present age of the son?
Let son’s age be be S
Then daughter’s is: S + 2
Woman’s age: S + 29, and also, 4(S + 2)
We then get: S + 29 = 4(S + 2)
S + 29 = 4S + 8
S – 4S = 8 – 29
– 3S = - 21
S, or son’s age is: 
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