SOLUTION: Three interferes A B C added to 15. What is the highest possible value if A X B X C

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Question 1111832: Three interferes A B C added to 15. What is the highest possible value if A X B X C
Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
Use inequality of arithmetic and geometric means for three variables.


It says  (see this Wikipedia article  https://en.wikipedia.org/wiki/Inequality_of_arithmetic_and_geometric_means) :



    For any 3 non-negative numbers  a, b  and  c


        %28a+%2B+b+%2B+c%29%2F3 >= root%283%2C+a%2Ab%2Ac%29,

        and inequality becomes the equality if and only if  a = b = c.



In your case, it means that if  a + b + c = 15,  then  a*b*c has the maximum value of 5*5*5 = 125  when  a = b = c = 5.


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Notice :   I don't know what these words of the condition  " Three interferes . . . "  mean.

I suspect that they should be  "Three integers . . . "  instead.