SOLUTION: Lucas is 9 years older than three times his son's age. In 5 years, the age of Lucas will be 6 years more than twice his son's age. Find their present age.

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Lucas is 9 years older than three times his son's age. In 5 years, the age of Lucas will be 6 years more than twice his son's age. Find their present age.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1110899: Lucas is 9 years older than three times his son's age. In 5 years, the age of Lucas will be 6 years more than twice his son's age. Find their present age.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
L, Lucas
c, Lucas'es son

This is the literal translation into equations:
system%28L=9%2B3c%2CL%2B5=6%2B2%28c%2B5%29%29

Solve the system for L and c.

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.
L = 9 + 3*S,             (1)

L + 5 = 6 + 2*(S+5).     (2)



Substitute (1) into (2).  You will get

9 + 3*S + 5 = 6 + 2S + 10,

S = 6 + 10 - 9 - 5 = 2.


Thus we found that the son is 2 years old.

Then Lucas (= the father of his son) is 9 + 3*2 = 9 + 6 = 15 years old.

--------------------
Do not ask me about the meaning of this problem.

I am not responsible for its meaning  (if the meaning does present here).

I am responsible for the correctness of the solution only.

It is the person who invented it is responsible for the meaning  (or for its absence).