Question 1110796: Six years age, Rosa was four times as old as her daughter. Ten years from now, she will be only twice as old as her daughter. How old are they now?
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617)   (Show Source):
Answer by ikleyn(52786)  (Show Source):
You can put this solution on YOUR website! .
Six years  ago, Rosa was four times as old as her daughter. Ten years from now, she will be only twice as old as her daughter.
How old are they now?
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r-6 = 4(d-6), (1)
r + 10 = 2*(d+10) (2)
From (1), express r = 4*(d-6) + 6 = 4d - 24 + 6 = 4d -18 and substitute it into (2). You will get
4d - 18 + 10 = 2*(d+10),
4d - 8 = 2d + 20 ====> 2d = 20+8 = 28 ====> d =  = 14.
Then r = 4*14-18 = 38.
Answer. d = 14, r = 38.
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There is a bunch of lessons on age word problems
- Age problems and their solutions
- A fresh formulation of a traditional age problem
- Really intricate age word problem
- Selected age word problems from the archive
- Age problems for mental solution
in this site.
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The referred lessons are the part of this online textbook under the topic "Age word problems".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
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Be aware: The solution by @josgarithmetic and his answer d = 14 and r = 46 are W R O N G.
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