SOLUTION: Richard is five years older than Sheila. Four times Sheila’s age increased by 3 years equals three time Richard’s age
diminished by 2 years. Find Richard’s age.
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diminished by 2 years. Find Richard’s age.
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Question 1098135: Richard is five years older than Sheila. Four times Sheila’s age increased by 3 years equals three time Richard’s age
diminished by 2 years. Find Richard’s age. Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! (1)
(2)
----------------------
(2)
and
(1)
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Multiply both sides of (1) by
(1)
Add (1) and (2)
(1)
(2)
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Richard is 15
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check:
(1)
(1)
(1)
and
(2)
(2)
(2)
(2)
OK
