SOLUTION: a sum of 1.85 pesos is composed of 5,10,25-centavo coins.If there were twice as many 5-centavo coins as there are 10-centavo coins;and if there are two or more 25 centavo coins tha

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Question 1096637: a sum of 1.85 pesos is composed of 5,10,25-centavo coins.If there were twice as many 5-centavo coins as there are 10-centavo coins;and if there are two or more 25 centavo coins than half the numbers of 5 centavo coins.How many coins of each kind?

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!

The number of 5c coins is twice the number of 10c coins. So

let x = number of 10c coins
then 2x = number of 5c coins

The number of 25c coins is 2 more than half the number of 5c coins; that means 2 more than the number of 10c coins. so

x+2 = number of 25c coins

The total value is 1.85 pesos, or 185c, so

25%28x%2B2%29%2B10%28x%29%2B5%282x%29+=+185
25x%2B50%2B10x%2B10x+=+185
45x%2B50+=+185
45x+=+135
x+=+3

So x = 3.

The number of 25c coins is x+2 = 5
The number of 10c coins is x = 3
The number of 5c coins is 2x = 6

Check:
5%2825%29%2B3%2810%29%2B6%285%29+=+125%2B30%2B30+=+185