SOLUTION: In 10 years time a father will be twice as old as his daughter.10 years ago he was six times as old as his daughter. How old is each now?
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Question 1089592: In 10 years time a father will be twice as old as his daughter.10 years ago he was six times as old as his daughter. How old is each now?
The condition is translated to these two equations
F + 10 = 2*(D + 10), (1)
F - 10 = 6*(D - 10). (2)
To solve them, express F = 6D - 50 from (2) and then substitute it into equation (1). You will get
(6D-50) + 10 = 2D + 20,
6D - 40 = 2D + 20 ====> 4D = 60 ====> D = = 15.
Answer. The daughter is 15 years old now; the father is F = 6D - 50 = 6*15 - 50 = 90 - 50 = 40 years old now.
