SOLUTION: Maria is 14 years older than Jean. If The product of their ages is 51. Find the ages of two girls

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Question 1087456: Maria is 14 years older than Jean. If
The product of their ages is 51. Find
the ages of two girls




Found 4 solutions by addingup, ikleyn, Fombitz, MathTherapy:
Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
x*x+14 = 51
x^2 = 37
x = 6 this is Jean
6+14 = 20 this is Maria

Answer by ikleyn(52798) About Me  (Show Source):
You can put this solution on YOUR website!
.
3 and 17 years.

To get this solution, find (MENTALLY) two factors of the number 51 that differ by 14.

Ignore the other solution: it is wrong and irrelevant.



Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
M=14%2BJ
MJ=51
Substituting,
%2814%2BJ%29J=51
J%5E2%2B14J-51=0
%28J-3%29%28J%2B17%29=0
Only positive solutions make sense here,
J-3=0
J=3
Now use either equation to solve for M.

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Maria is 14 years older than Jean. If
The product of their ages is 51. Find
the ages of two girls
You just need to find 2 numbers that, when MULTIPLIED, gives you 51, and when SUBTRACTED, equals 14.
In other words, try to find 2 FACTORS of 51 that have a difference of 14.