SOLUTION: In chemistry class, 14 liters of a 12% alcohol solution must mixed with a 20% solution to get a 13% solution. How many liters of the 20% solutuon are needed?
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Question 1079726: In chemistry class, 14 liters of a 12% alcohol solution must mixed with a 20% solution to get a 13% solution. How many liters of the 20% solutuon are needed? Found 2 solutions by Alan3354, ikleyn:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! In chemistry class, 14 liters of a 12% alcohol solution must mixed with a 20% solution to get a 13% solution. How many liters of the 20% solutuon are needed?
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All L liters of 20%
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14*12 + L*20 = (14*L)*13
Solve for L
You can put this solution on YOUR website! .
In chemistry class, 14 liters of a 12% alcohol solution must mixed with a 20% solution to get a 13% solution. How many liters of the 20% solution are needed?
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Let L be the volume, in liters, of the 20% solution to mix.
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14*12 + L*20 = (14+L)*13
Solve for L.
