SOLUTION: The sum of the ages of Mr.Daniel and his daughter is 60 years. 5 years ago, the ratio of their ages was 1:4. 1.how old are they now? 2.find the difference between their ages

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Question 1075816: The sum of the ages of Mr.Daniel and his daughter is 60 years. 5 years ago, the ratio of their ages was 1:4. 1.how old are they now? 2.find the difference between their ages

Found 2 solutions by Alan3354, ankor@dixie-net.com:
Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
The sum of the ages of Mr.Daniel and his daughter is 60 years. 5 years ago, the ratio of their ages was 1:4.
----
5 years ago the sum was 50 --> 10 & 40
etc.
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1.how old are they now? 2.find the difference between their ages

Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
The sum of the ages of Mr.Daniel and his daughter is 60 years.
let f = the father's present age (Daniel)
let d = the daughter's age
therefore
f + d = 60
5 years ago, the ratio of their ages was 1:4.
=
Cross multiply
f - 5 = 4(d-5)
f - 5 = 4d - 20
f - 4d = -20 + 5
f - 4d = -15
use elimination on the 2 equations
f + d = 60
f -4d = -15
-------------subtraction eliminates f, find d
0 + 5d = 75
5d = 75
d = 75/5
d = 15 yrs is the daughter's age
1.how old are they now?
Find Daniel's age
60 - 15 = 45 yrs
2.find the difference between their ages
45 - 15 = 30 yrs
:
:
Confirm this, 5 yrs ago they were 10 and 40 a ratio of 1:4