SOLUTION: Of 2 women, Jayde and Anne, Anne is currently 3 times as old as Jayde. 10 years ago she was 5 times as old as Jayde. What are their current ages?

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Question 1073058: Of 2 women, Jayde and Anne, Anne is currently 3 times as old as Jayde.
10 years ago she was 5 times as old as Jayde. What are their current ages?
Found 2 solutions by ikleyn, josmiceli:
Answer by ikleyn(52812)   (Show Source):
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.

The condition produces these two equations for the women's current aje A = 3J, (1) A - 10 = 5*(J-10). (2) Substitute an expression A = 3J of (1) into (2) to get 3J - 10 = 5(J-10), 3J - 10 = 5J - 50, 50 - 10 = 5J - 3J, 40 = 2J ---> J = = 20. Answer. Jayde is currently 20 years old. Anny is 3*20 = 60 years old.

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    - Age problems and their solutions
    - A fresh formulation of a traditional age problem
    - Really intricate age word problem
    - Selected age word problems from the archive
in this site.

Read them and become an expert in solving age problems.

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    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Age word problems".

Answer by josmiceli(19441)   (Show Source):
You can put this solution on YOUR website!
Let = Jayde's age now
Let = Anne's age now
-------------------------------
(1)
(2)
----------------------------
(2)
(2)
By substitution:
(2)
(2)
(2)
and
(1)
(1)
(1)
--------------------
Jayde's age now is 20
Anne's age now is 60
------------------------
check:
(2)
(2)
(2)
(2)
OK