SOLUTION: Ten years ago a man was six times as old as his daughter . After 10 years ,he will be twice as old as his daughter .find the present ages

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Question 1071658: Ten years ago a man was six times as old as his daughter . After 10 years ,he will be twice as old as his daughter .find the present ages
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Ten years ago,
M-10=6%28D-10%29
In ten years,
M%2B10=2%28D%2B10%29
From the first equation,
M-10=6D-60
1.M-6D=-50
From the second,
M%2B10=2D%2B20
2.M-2D=10
Subtracting 1 from 2,
M-2D-M%2B6D=10-%28-50%29
4D=60
D=15
So then,
M-2%2815%29=10
M-30=10
M=40