SOLUTION: Sue is two years older than Mary. Eleven years ago, Sue was twice as old as Mary. How old is each girl now?

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Question 1064789: Sue is two years older than Mary. Eleven years ago,
Sue was twice as old as Mary. How old is each girl now?

Found 2 solutions by addingup, Edwin McCravy:
Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website!
Sue = Mary+2
S-11 = 2(M-11) substitute here for Sue
M+2-11 = 2M-22
M-9 = 2M-22
-M = -13 multiply both sides times -1
M = 13 Mary is 13
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Check:
Sue is M+2 = 13+2 = 15
and
S-11 = 2(M-11)
15-11 = 2(13-11)
4 = 26-22 Correct.
:
John

Answer by Edwin McCravy(20060) (Show Source):
You can put this solution on YOUR website!
Sue is two years older than Mary. Eleven years ago,
Sue was twice as old as Mary. How old is each girl now?

Sue's age now = S Mary's age now = M Sue's age 11 years ago = S-11 Mary's age 11 years ago = M-11

Sue is two years older than Mary.

S = M+2

Eleven years ago, Sue was twice as old as Mary.

S-11 = 2(M-11) Solve this system of equations by substitution: Edwin