Question 1062746: When santy ad lorna were married, his age was 3/2 of her age. If on their golden wedding anniversary, Santy's age will be 8/7 of lorna's age, how old will each of them be on their golden anniversary.
Answer by ikleyn(52781)   (Show Source):
You can put this solution on YOUR website! .
When santy ad lorna were married, his age was 3/2 of her age. If on their golden wedding anniversary,
Santy's age will be 8/7 of lorna's age, how old will each of them be on their golden anniversary.
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S/L = 3/2, (1) ("When santy ad lorna were married, his age was 3/2 of her age")
 =  (2) ("If on their golden wedding anniversary, Santy's age will be 8/7 of lorna's age")
Rewrite equations (1) and 2) equivalently
2S = 3L, (1')
7*(S+50) = 8*(L+50) (2')
or
2S - 3L = 0,
7S + 350 = 8L + 400,
or
2S - 3L = 0, (1'')
7S - 8L = 50. (2'')
Now multiply (1'') by 7 and (2'') by 2 (both sides), then distract. You will get
-7*(3L) - (-8L)*2 = -2*50, or
-5L = -100 ---> 5L = 100 ---> L =  = 20.
Thus Lorna' present age is 20 years. Then Santy is  = 30 years old.
Answer. In 50 years Santy will be 80 years old, Lorna will be 70 years old.
Wish them to happily celebrate their golden anniversary.
There is a bunch of lessons on age word problems
- Age problems and their solutions
- A fresh formulation of a traditional age problem
- Really intricate age word problem
- Selected age word problems from the archive
in this site.
Read them and become an expert in solving age problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Age word problems".
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