SOLUTION: son and fathers age is 74 years.the ratio of their age was 7:2 since 10 years ago.what is the ratio of their age will stand after 10 year?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: son and fathers age is 74 years.the ratio of their age was 7:2 since 10 years ago.what is the ratio of their age will stand after 10 year?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1060312: son and fathers age is 74 years.the ratio of their age was 7:2 since 10 years ago.what is the ratio of their age will stand after 10 year?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
As I understand this:
The sum of son and fathers age is 74 years.
s + f = 74
f = (74-s); use this form for substitution
the ratio of their age was 7:2, 10 years ago.
%28%28f-10%29%29%2F%28%28s-10%29%29 = 7%2F2
Cross multiply
7(s-10) = 2(f-10)
7s - 70 = 2f - 20
7s = 2f - 20 + 70
7s - 2f = 50
replace f with (74-s)
7s - 2(74-s) = 50
7s - 148 + 2s = 50
9s = 50 + 148
9s = 198
s = 198/9
s = 22 yrs if the son's age
and
74 - 22 = 52 is Dad's age
:
what is the ratio of their age after 10 year?
add 10 yrs to their ages
62%2F32 = 31%2F16. a Ratio of 31:16
: