SOLUTION: The ages of a brother and the younger sisters sum to 44 years. In five years the brother will be twice as old as his sister. Find the age of the brother and sister.
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Question 1057373: The ages of a brother and the younger sisters sum to 44 years. In five years the brother will be twice as old as his sister. Find the age of the brother and sister. Answer by ikleyn(52803) (Show Source):
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The ages of a brother and the younger sisters sum to 44 years. In five years the brother will be twice as old as his sister.
Find the age of the brother and sister.
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Let B be the brother's present age.
Then the sister's present age is 44-B.
In 5 years the brother will be (B+5) years old.
while sister will be 44-B + 5.
We are given that
B+5 = 2(44-B+5).
Simplify and solve for B:
B + 5 = 88 - 2B + 10,
B + 2B = 88+10-5,
3B = 93,
B = = 31.
Answer. The brother's present age is 31 year. The sister is 44-31 = 13 years old.
