SOLUTION: brian is 4 years older than sam five years ago the sum of there ages was 48 how old are they now

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Question 1054542: brian is 4 years older than sam five years ago the sum of there ages was 48 how old are they now
Found 2 solutions by Fombitz, stanbon:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1.B=S%2B4
Five years ago,
%28B-5%29%2B%28S-5%29=48
B%2BS-10=48
B%2BS=58
From eq. 1,
B-S=4
Add the two equations,
B%2BS%2BB-S=58%2B4
2B=62
B=31
So,
31=S%2B4
S=27

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
brian is 4 years older than sam five years ago the sum of there ages was 48 how old are they now
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B = S + 4
B-5 + S-5 = 48
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Substitute for "B" and solve for "S:
S+4-5 + S-5 = 48
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2S - 6 = 48
2S = 54
Sam's age = 27 yrs
Brian = S+4 = 31 yrs
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Cheers,
Stan H.
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