SOLUTION: The father age 10 years ago was 35 year more than twice of his son age after how many years from now will the father be twice of his son

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Question 1053460: The father age 10 years ago was 35 year more than twice of his son age after how many years from now will the father be twice of his son

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = father's age now
Let +b+ = son's age now
----------------------------
+a+-+10+=+2%2A%28+b+-+10+%29+%2B+35+
+a+-+10+=+2b+-+20+%2B+35++
(1) +a+=+2b+%2B+25+
---------------------
Let +n+ = the number of years from
now when The father is twice the age
of the son
+a+%2B+n+=+2%2A%28+b+%2B+n+%29+
+a+%2B+n+=+2b+%2B+2n+
(2) +n+=+a+-+2b+
------------------------
Substitute (1) into (2)
(2) +n+=+2b+%2B+25+-+2b+
(2) +n+=+25+
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In 25 years the father will be twice the age of the son
( definitely get a 2nd opinion on this )