Question 1053218: A father is three times as old as the son. Nine years ago the father was four times as old as the son find the present ages Answer by ikleyn(52782) (Show Source):
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A father is three times as old as the son. Nine years ago the father was four times as old as the son find the present ages.
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F = 3S, (1) ("A father is three times as old as the son")
F-9 = 4*(S-9) (2) ("Nine years ago the father was four times as old as the son")
Substitute (1) into (2). You will get
3S-9 = 4(S-9),
3S-9 = 4S - 36 ---> S = 27.
The son is 27 years old now. The father is 3*27 = 81 years old now.
Answer. The son is 27 years old now. The father is 81 years old now.
