SOLUTION: a mother is 5 times older than her daughter, 5 years ago the sum of their ages was 50, find their present ages?

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Question 1052832: a mother is 5 times older than her daughter, 5 years ago the sum of their ages was 50, find their present ages?

Found 2 solutions by Alan3354, advanced_Learner:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
a mother is 5 times older than her daughter, 5 years ago the sum of their ages was 50, find their present ages?
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a mother is 5 times older than her daughter
--
1 time older = 2 times as old
2 times older = 3 times as old
3 times older = 4 times as old
4 times older = 5 times as old
5 times older = 6 times as old
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M = 6D
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5 years ago the sum of their ages was 50 --> the is now 60
M + D = 60
S for M
6D + D = 60
D = 60/7 years
M = 360/7 years

Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
10 and 50 years old respectively.
M=5D
M-5%2BD-5=50
Substitute M with 5D
5D-5%2BD-5=50
6D=60
D=10 present age
and Mother is
M=50 years old
check five years ago
mom 45 and daughter 5
sum is 50 years old.