SOLUTION: five years ago a mother was twice as old ss her son. in 6 yrs time, the sum of their age will be 82. find there percentage age ??

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Question 1052164: five years ago a mother was twice as old ss her son. in 6 yrs time, the sum of their age will be 82. find there percentage age ??
Found 2 solutions by jorel555, advanced_Learner:
Answer by jorel555(1290) About Me  (Show Source):
You can put this solution on YOUR website!
Let s be the age of the son five years ago. Then the mother would be 2s. So:
s+5+6+2s+5+6=82
3s=60
s=20
s+5=25
2s+5=45
45/25=1.8 is the ratio of their ages right now. ☺☺☺☺

Answer by advanced_Learner(501) About Me  (Show Source):
You can put this solution on YOUR website!
m and s age now
age five years ago
m-5
s-5
age six years from no
m+6
s+6

m-5=2%28s-5%29
m%2B6%2Bs%2B6=82
re-arrange
m-2s=%28-5%29
m%2Bs=70
Solved by pluggable solver: Linear System solver (using determinant)
Solve:
+system%28+%0D%0A++++1%5Cm+%2B+-2%5Cs+=+-5%2C%0D%0A++++1%5Cm+%2B+1%5Cs+=+70+%29%0D%0A++

Any system of equations:


has solution

or



(m=45, s=25}