SOLUTION: Help me, I am able to do age algebra problems, but this one confuses me. I have tried to solve it, but I know the answer won't be identity: Find three consecutive odd integers

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Question 1047674: Help me, I am able to do age algebra problems, but this one confuses me. I have tried to solve it, but I know the answer won't be identity:
Find three consecutive odd integers where the sum of the first and second is equal to six less than twice the third integer.
x+x+2=2(x+4)-6
2x+2=2x+8-6
2x+2=2x+2
2=2
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find three consecutive odd integers where the sum of the first and second is equal to six less than twice the third integer.
x+x+2=2(x+4)-6
2x+2=2x+8-6
2x+2=2x+2
2=2
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2 does equal 2.
--> x can be any integer, odd or even.
There is no unique solution.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Find three consecutive odd integers where the sum of the first and second is equal to six less than twice the third integer.
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Even numbers are multiples of 2: 2x
Odd numbers are 1 more than or one less then an even number.
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3 consecutive odd numbers
1st:: 2x-1
2nd:: 2x+1
3rt:: 2x+3
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Equation::
(2x-1)+(2x+1) = 2(2x+3)-6
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4x = 4x
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Ans:: x can have any integer value.
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Cheers,
Stan H.
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