SOLUTION: A passenger train traveled 100 miles in the same amount of time it took a fright train to travel 80 miles. The rate of the freight was 5 miles per hour slower than the rate of the
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Question 1047445: A passenger train traveled 100 miles in the same amount of time it took a fright train to travel 80 miles. The rate of the freight was 5 miles per hour slower than the rate of the passenger train. Find the rate of the passenger train Found 2 solutions by josmiceli, MathTherapy:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = time in hrs for both trains
Let = speed of the passenger train in mi/hr = speed of the freight train in mi/hr
---------------------
Equation for passenger train:
(1)
Equation for freight train:
(2)
------------------------
(1)
and
(2)
(2)
(2)
(2) mi/hr
and
The rate of the passenger train is 25 mi/hr
---------------
check:
(1)
(1)
(1) hrs
and
(2)
(2)
(2)
(2) hrs
OK
You can put this solution on YOUR website!
A passenger train traveled 100 miles in the same amount of time it took a fright train to travel 80 miles. The rate of the freight was 5 miles per hour slower than the rate of the passenger train. Find the rate of the passenger train
Let rate of passenger train be S
Then rate of freight train is: S - 5
We then get the following TIME equation:
100(S - 5) = 80S ------ Cross-multiplying
100S - 500 = 80S
100S - 80S = 500
20S = 500
S, or rate of passenger train was: , or
