SOLUTION: A father is 46 years older than his son. In 10 years he'll be twice as old as his son what are their present ages

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Question 1046856: A father is 46 years older than his son. In 10 years he'll be twice as old as his son what are their present ages
Answer by stanbon(75887) About Me  (Show Source):
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A father is 46 years older than his son. In 10 years he'll be twice as old as his son what are their present ages
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F = S + 46
F+10 = 2(S+10)
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Substitute for "F" and solve for "S"::
S + 46 + 10 = 2S + 20
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S = 36 yrs (son's age now)
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F = S + 46 = 36+46 = 82 yrs (Father's age now)
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Cheers,
Stan H.
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