SOLUTION: Jack is 2 times as old as Lacy. 7years ago the sum of their ages was 28. How old are they now?

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Question 1046343: Jack is 2 times as old as Lacy. 7years ago the sum of their ages was 28. How old are they now?
Answer by ikleyn(52781) About Me  (Show Source):
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Jack is 2 times as old as Lacy. 7 years ago the sum of their ages was 28. How old are they now?
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J = 2L,       (1)   ( "Jack is 2 times as old as Lacy" )

Since "7 years ago the sum of their ages was 28", then the sum of their ages now is 28 + 7 + 7 = 42 now:

J + L = 42.   (2) 

Substitute (1) into (2. You will get

2L + l = 42,

3L = 42,

L = 42%2F3 = 14.

Answer.  Lacy is 14 years now. Jack is 14*2 = 28 years old now.

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    - Age problems and their solutions
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    - Age problem for the day of April, 1
in this site.

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