SOLUTION: Solve: John has three sons. The eldest son is four times older than his second son. The second son is four years older than the youngest son. The youngest son is exactly half the a

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Question 1045827: Solve: John has three sons. The eldest son is four times older than his second son. The second son is four years older than the youngest son. The youngest son is exactly half the age of the eldest son. How old is each son?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39616) About Me  (Show Source):
Answer by MathTherapy(10551) About Me  (Show Source):
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Solve: John has three sons. The eldest son is four times older than his second son. The second son is four years older than the youngest son. The youngest son is exactly half the age of the eldest son. How old is each son?
FYI: With the second son being S, and the eldest son being FOUR TIMES OLDER than the second son (S), the ELDEST son would be 4S + S = 5S, or

FIVE TIMES THE SECOND SON'S age. I think this has been "preached" on this site many, many times over, but still seems to be falling on "deaf ears."

It's EXTREMELY STUPID to create a problem such as this that reads: FOUR TIMES OLDER when in fact it should be FOUR TIMES AS OLD. It irks me to see

these stupid problems, and I hope one day that whomever is creating them will DESIST from doing so.