SOLUTION: In 2005 Susidu will 3 times old in age than Sasidu. in 2010 Susidu will 30 years old than Sasidu, In which year Susidu's age double as Sasidu's age? (please explain the method)
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-> SOLUTION: In 2005 Susidu will 3 times old in age than Sasidu. in 2010 Susidu will 30 years old than Sasidu, In which year Susidu's age double as Sasidu's age? (please explain the method)
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Question 1045130: In 2005 Susidu will 3 times old in age than Sasidu. in 2010 Susidu will 30 years old than Sasidu, In which year Susidu's age double as Sasidu's age? (please explain the method) Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! Let = Susidu's age in 2005
Let = Sasidu's age in 2005 = Susidu's age in 2010 = Sasidu's age in 2010
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(1)
(2)
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(2)
(2)
Substitute (1) into (2)
(2)
(2)
(2)
and
(1)
(1)
(1)
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45 = Susidu's age in 2005
15 = Sasidu's age in 2005
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In what year is Susidu's age double Sasidu's?
Let = the number of years after 2005
that is true
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2005 + 15 = 2020
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In 2020, Susidu's age is double Sasidu's
check:
and
and
OK
