SOLUTION: The sum of the ages of Mr.Lin and his son is 38 years. In three years' time, Mr.Lin will be three times as old as his son. Find thier present ages.
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Question 1044503: The sum of the ages of Mr.Lin and his son is 38 years. In three years' time, Mr.Lin will be three times as old as his son. Find thier present ages. Found 2 solutions by josgarithmetic, ikleyn:Answer by josgarithmetic(39620) (Show Source):
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The sum of the ages of Mr.Lin and his son is 38 years. In three years' time, Mr.Lin will be three times as old as his son. Find thier present ages.
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Let L = Mr.Lin's present age,
S = his son's present age.
First equation is
L + S = 38. (1)
The second equation is
L + 3 = 3*(S+3) (2) ("In three years' time, Mr.Lin will be three times as old as his son.")
From (1), express S = 38-L and substitute it into (2). You will get
L + 3 = 3*((38-L)+3), or
L + 3 = 114 - 3L + 9,
4L = 114 + 9 - 3,
4L = 120,
L = 30.
Answer. Mr.Lin's present age is 30 years now. His son is 8 years old now.
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