Question 1043017: Jose is 3 times as old as Wally. Five years from now, The sum of their ages is 42. How old are they now? Answer by ikleyn(52776) (Show Source):
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Jose is 3 times as old as Wally. Five years from now, The sum of their ages is 42. How old are they now?
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Let J = Jose's age now; W = Wally's age now. Then
J = 3W, (1) ( "Jose is 3 times as old as Wally" )
(J+5) + (W+5) = 42. (2) ( "Five years from now, The sum of their ages is 42" )
Simplify 2):
J + W + 10 = 42, or
J + W = 42-10 = 32.
Now substitute J= 3W from (1) into the last equation. You will have
3W + W = 32.
Can you complete the solution from this point?
