SOLUTION: five years ago mike was twice as old as Berto.The sum of their ages in 6 years will be 40 years.What is the present age of each?

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Question 1040041: five years ago mike was twice as old as Berto.The sum of their ages in 6 years will be 40 years.What is the present age of each?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = Mike's age now
Let +b+ = Berto's age now
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(1) +a+-+5+=+2%2A%28+b+-+5+%29+
(2) +a+%2B+6+%2B+b+%2B+6+=+40+
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(1) +a+-+5+=+2b+-+10+
(1) +-a+%2B+2b+=+5+
and
(2) +a+%2B+b+=+28+
-----------------------
Add (1) and (2)
(2) +a+%2B+b+=+28+
(1) +-a+%2B+2b+=+5+
-----------------------
+3b+=+33+
+b+=+11+
and
(2) +a+%2B+b+=+28+
(2) +a+%2B+11+=+28+
(2) +a+=+17+
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Mike is 17
Berto is 11
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check:
(1) +a+-+5+=+2%2A%28+b+-+5+%29+
(1) +17+-+5+=+2%2A%28+11+-+5+%29+
(1) +12+=+2%2A6+
(1) +12+=+12+
OK