SOLUTION: a man, when asked the ages of his two sons, replied that 18 more than the sum of their ages is double the age of the older. Six less than the difference of their ages is the age of

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Question 1028686: a man, when asked the ages of his two sons, replied that 18 more than the sum of their ages is double the age of the older. Six less than the difference of their ages is the age of the youngest. what are their ages
Found 2 solutions by Edwin McCravy, mananth:
Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the age of the older son.
Let y = the age of the younger son.

a man, when asked the ages of his two sons, replied that
18 more than the sum of their ages 
which is:

(x+y)+18

is double the age of the older
which is

2x

So 

(x+y)+18 = 2x

Six less than the difference of their ages 
which is

(x-y)-6

is the age of the youngest. 
which is

y

So 

(x-y)-6 = y

what are their ages

system%28%28x%2By%29%2B18+=+2x%2C%28x-y%29-6+=+y%29

Simplify and solve this system of equations

for x and y.

Edwin

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!

a man, when asked the ages of his two sons,
Let younger son be x
and elder be y
18 more than the sum of their ages is double the age of the older.
(x+y)+18 = 2y
y-x=18...................(1)
Six less than the difference of their ages is the age of the youngest. what are their ages
(y-x)-6=x
y-2x=6........................(2)
subtract (1) & (2)
x=12
y=30