Question 1028359: in 28 years, a woman will be twice as old as she will be in two years. How old is she now? Found 2 solutions by ikleyn, josgarithmetic:Answer by ikleyn(52800) (Show Source):
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in 28 years, a woman will be twice as old as she will be in two years. How old is she now?
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W + 28 = 2(W + 2),
W + 28 = 2W + 4,
28 - 4 = 2W - W,
W = 24.
Answer. Woman present age is 24 years.
Check: in two years W + 2 = 26.
in 28 years W + 28 = 24 + 28 = 52.
52 = 2*26. OK.
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