Question 1027190: A cashier has a total of 90 bills,made up of fives and tens. The totL value of the money is 645. How many of each kind does he have. Answer by Edwin McCravy(20056) (Show Source):
Let the number of fives be x
Let the number of tens be y
Value Value
Type Number of of
of of EACH ALL
bill bills bill bills
-------------------------------------------
fives x $5 $5x
tens y $10 $10y
-------------------------------------------
TOTALS 90 ----- $645
The first equation comes from the second column.
x + y = 90
The second equation comes from the last column.
5x + 10y = 645
So we have the system of equations:
.
We solve by substitution. Solve the first equation for y:
x + y = 90
y = 90 - x
Substitute (90 - x) for y in 5x + 10y = 645
5x + 10(90 - x) = 645
5x + 900 - 10x = 645
-5x + 900 = 645
-5x = -255
x = 51 = the number of fives.
Substitute in y = 90 - x
y = 90 - (51)
y = 39 tens.
Checking: 51 fives is $255 and 39 tens is $390
That's 90 bills.
And indeed $255 + $390 = $645
Edwin