Question 1024017: How many liters of water must be added to 26 liters of a 15% antifreeze solution to dilute it to a 12% solution? Found 2 solutions by robertb, josmiceli:Answer by robertb(5830) (Show Source):
You can put this solution on YOUR website! 0.15*26+0*x = 0.12(26+x)
==> 3.9 = 3.12 + 0.12x
==> 0.78 = 0.12x
==> 6.5 = x, the amount of water in liters to add.
You can put this solution on YOUR website! Let = liters of water to be added = liters of antifreeze in 15% solution
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6.5 liters of water must be added
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check:
OK
