SOLUTION: Sue is three times Mike's age. In four years, Sue will be two years older than twice Mike's age then. How old is each?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Sue is three times Mike's age. In four years, Sue will be two years older than twice Mike's age then. How old is each?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1013871: Sue is three times Mike's age. In four years, Sue will be two years older than twice Mike's age then. How old is each?
Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
.
Sue is three times Mike's age. In four years, Sue will be two years older than twice Mike's age then. How old is each?
----------------------------------------------------------- 

Your system of equations is

s     = 3m,           (1)
s + 4 = 2 + 2(m+4).   (2)

Substitute (1) into (2). You will get

3m + 4 = 2m + 8 + 2,

m = 8 + 2 - 4 = 6.

Answer. Mike is 6 years, Sue is 18 years now.