SOLUTION: AGES OF FATHER AND HIS SON ARE IN RATIO OF 10:3 EIGHT YEARS AFTER THEIR AGES WOULD BE IN THE RATIO 12:5 FIND THEIR AGES

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Question 1005423: AGES OF FATHER AND HIS SON ARE IN RATIO OF 10:3 EIGHT YEARS AFTER THEIR AGES WOULD BE IN THE RATIO 12:5 FIND THEIR AGES
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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AGES OF FATHER AND HIS SON ARE IN RATIO OF 10:3
let x = the multiplier
then
10x = the father's age
3x = the son's
:
EIGHT YEARS AFTER THEIR AGES WOULD BE IN THE RATIO 12:5
%28%2810x%2B8%29%29%2F%28%283x%2B8%29%29 = 12%2F5
Cross multiply
5(10x+8) = 12(3x+8)
50x + 40 = 36x + 96
50x - 36x = 96 - 40
14x = 56
x = 56/14
x = 4 is the multiplier
:
FIND THEIR AGES
10(4) = 40 yrs is Dad's age
3(4) = 12 yrs is Son's age
:
:
Confirm this by finding their ages in 8 yrs
Dad's 48; Son's 20
48:20 reduces to 12:5