SOLUTION: Ken is 6 years older then Sue, who is 6 years older then Betty, who is 6 years older than Jason. If Jason's age is half of Ken's age, how old is Jason

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Question 1004999: Ken is 6 years older then Sue, who is 6 years older then Betty, who is 6 years older than Jason. If Jason's age is half of Ken's age, how old is Jason
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
>>Ken is 6 years older then Sue, who is 6 years older then Betty,
who is 6 years older than Jason.<<
A little thinking about the statement above will tell you that 
Ken is 18 years older than Jason.

So K+=+J+%2B+18

>>Jason's age is half of Ken's age,<<
J+=+expr%281%2F2%29K

So we have the system of equations:

system%28K=J%2B18%2CJ=expr%281%2F2%29K%29

Since the question is

>>how old is Jason?<<
We substitute J+18 for K in J=expr%281%2F2%29K

J=expr%281%2F2%29K
J=expr%281%2F2%29%28J%2B18%29%29

Multiply both sides by 2 to clear the fraction:

2J=J%2B18

Subtract J from both sides:

J=18, so Jason is 18.

Checking the words:

>>Ken is 6 years older then Sue, who is 6 years older then Betty,
who is 6 years older than Jason. Jason's age is half of Ken's age.<<
Betty is 6 years older than Jason, so Betty is 24.
Sue is 6 years older than Betty, so Sue is 30.
Ken is 6 years older than Sue, so Ken is 36.
And indeed, Jason's age, which is 18 is half of Ken's age, 
which is 36.
 
Edwin