SOLUTION: A boy is 10 years older than his brother. In 4 years he will be twice as old as his brother. Find the present age of each

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Question 1004978: A boy is 10 years older than his brother. In 4 years he will be twice as old as
his brother. Find the present age of each
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A boy is 10 years older than his brother. In 4 years he will be twice as old as
his brother. Find the present age of each
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Equation:
y = r + 10
y+4 = 2(r+4)
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Substitute for "y" and solve for "r"::
r+10 + 4 = 2r + 8
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r = 6 (Brother's age now)
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y = r+10 = 16 (Boy's age now)
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Cheers,
Stan H.
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