Question 1004296: If father age is four times than his son and after 24 years, father age is twice as his son. What is their present age? Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi there,
If father age is four times than his son
F = 4S
after 24 years, father age is twice as his son
F + 24 = 2(S + 24)
Replace F with 4S from first equation.
4S + 24 = 2(S + 24)
4S + 24 = 2S + 48
Collect like terms
4S - 2S = 48 - 24
2S = 24
S = 12
Son = 12 years old
Father = 48 years old
Hope this helps :-)
