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Age problem for three participants
Problem 1Jack's age plus Marie's age is 27; Jack's age plus Fred's age is 38; Marie's age plus Fred's age is 33. How old is Jack?
Solution
Let j, m, f be their ages. Then
j + m = 27, (1)
j + f = 38, (2)
m + f = 33. (3)
The method to solve this system is as follows.
Add equations (1), (2) and (3) (both left sides and right sides). You will get
2*(j + m + f) = 27 + 38 + 33 = 98, or
j + m + f = 49. (4) ( <<<--- 49 = )
Now, subtract equation (1) from (4). You will get
f = 49 - 27 = 22.
Next, subtract equation (2) from (4). You will get
m = 49 - 38 = 11.
Finally, subtract equation (3) from (4). You will get
j = 49 - 33 = 16.
Answer. Jack is 16, Marie is 11, and Fred is 22 years old.
The lesson to learn from this solution is the method/trick for solving this special system of equations.
Actually, this method which works in many other similar cases. See the lessons
- The tricks to solve some word problems with three and more unknowns using mental math
- Joint-work problems for 3 participants (Problem 2)
in this site.
My other lessons on age word problems in this site are
- Age problems and their solutions
- HOW TO algebraize and to solve age problems?
- A fresh formulation of a traditional age problem
- Intricate age word problems
- Challenging age word problems
- Age problems for mental solution
- Some unusual age word problems
- Age problems with a defective sum of ages
- Miscellaneous age problems
- Entertainment age problems
- Age problem for the day of April, 1
- OVERVIEW of lessons on age problems
Use this file/link ALGEBRA-I - YOUR ONLINE TEXTBOOK to navigate over all topics and lessons of the online textbook ALGEBRA-I.
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