SOLUTION: Use integration method to find the volume generated by two curves, {{{y^2=4x}}} and {{{y^2=4(2-x)}}} ,turning 360 degrees, setting x-axis as the pivot.

Algebra ->  Testmodule -> SOLUTION: Use integration method to find the volume generated by two curves, {{{y^2=4x}}} and {{{y^2=4(2-x)}}} ,turning 360 degrees, setting x-axis as the pivot.      Log On


   



Question 995439: Use integration method to find the volume generated by two curves, y%5E2=4x and y%5E2=4%282-x%29 ,turning 360 degrees, setting x-axis as the pivot.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Use integration method to find the volume generated by two curves, y%5E2=4x and y%5E2=4%282-x%29 ,turning 360 degrees, setting x-axis as the pivot.
--------------------
graph%28300%2C300%2C-1%2C4%2C-1%2C4%2C2sqrt%28x%29%2C2sqrt%282-x%29%29
-----------
You can see in the graph that the 2 curves are symmetrical about x = 1, and about the x-axis.
----
--> find the volume of the left half rotated about the x-axis.
-----------
y+=+2sqrt%28x%29 from 0 to 1:
Using disks centered on the x-axis:
Vol = pi*r^2*dx
Vol+=+pi%2A%282sqrt%28x%29%29%5E2dx
Vol+=+4pi%2Axdx
INT+=+2pi%2Ax%5E2
--> Vol = 2pi per half
Total volume = 4pi cubic units.