SOLUTION: finding two consecutive even integers such that the smaller added to three times the larger gives a sum of 54

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Question 13203: finding two consecutive even integers such that the smaller added to three times the larger gives a sum of 54
Answer by akmb1215(68) About Me  (Show Source):
You can put this solution on YOUR website!
Two consecutive even integers, as variables, can be written as n and n+2 (it is n+2 because the next even integer is 2 more than the previous one - like 2 and 4.). So, your equation for this problem will be n+%2B+3%28n+%2B+2%29+=+54. Start solving by using the distributive property to get n+%2B+3n+%2B+6+=+54. Combine like terms to get 4n+%2B+6+=+54. Move the 6 to the other side of the equal sign to get 4n+=+48. Divide to solve for n, and you get n+=+12. The answer to your question is 12 and 14.