Question 1187272: One number is 10 more than a second number. If the product of the two numbers is 144, what are the two numbers?
Found 3 solutions by ikleyn, Alan3354, MathTherapy: Answer by ikleyn(52784) (Show Source):
You can put this solution on YOUR website! .
There are two pairs of such numbers.
One pair is (8,18). Another pair is (-8,-18).
Write and solve the equation
x*(x+10) = 144
Reduce it to the standard quadratic form and then solve by factoring or using the quadratic formula.
Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! One number is 10 more than a second number. If the product of the two numbers is 144, what are the two numbers?
==================
Try pairs of integer factors of 144: 2*72, 3*48, etc.
-----
To solve it algebraically,
x*(x+10) = 144
x^2 + 10x - 144 = 0
==========================
Now, to factor it, you need to find 2 numbers that differ by 10 and have a product of 144.
==================
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
If they were not integers, you would have to use the quadratic equation or complete the square.
----
eg:
One number is 10 more than a second number. If the product of the two numbers is 154, what are the two numbers?
---
x^2 + 10x - 154 = 0
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) |
Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.
First, we need to compute the discriminant : .
Discriminant d=716 is greater than zero. That means that there are two solutions: .


Quadratic expression can be factored:

Again, the answer is: 8.37908816025965, -18.3790881602597.
Here's your graph:
 |
===========
The solver always says it can be factored, but not necessarily with integers.
Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!
One number is 10 more than a second number. If the product of the two numbers is 144, what are the two numbers?
Correct answer:
|
|
|