SOLUTION: Vernon, Joshua, and Dino are painting a house. Working together they can paint the house is 6 hours. Working alone Vernon can paint the house in 15 hours and Dino can paint the hou
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Question 1172330: Vernon, Joshua, and Dino are painting a house. Working together they can paint the house is 6 hours. Working alone Vernon can paint the house in 15 hours and Dino can paint the house in 20 hours. How long would it take Joshua to paint the house working alone? Found 2 solutions by ikleyn, greenestamps:Answer by ikleyn(52785) (Show Source):
The combined rate of work of the three workers is of the job per hour.
The individual rates of the two participants are and of the job per hour.
Then the rate of work of the remained third participant is the difference
- - = = = of the job per hour.
Hence, Joshua can complete the job in 20 hours, working alone. ANSWER
The referred lessons are the part of this textbook under the topic
"Rate of work and joint work problems" of the section "Word problems".
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The lessons to learn from this solution :
1) You can solve this problem/(such problems) even without using equations.
Freely manipulating fractions is enough.
2) Use the notion "rate of work" and remember:
a) when two or three persons work together, their combined rate of work is the sum of individual rates;
b) when the combined rate of three workers is given along with the individual rates of two of them, then the rate
of the third worker is the difference of combined rate and two given individual rates.
Here is an alternative to the standard algebraic solution shown by tutor @ikleyn.
Many students prefer this method because it avoids using fractions. Note, however, that the required arithmetic is nearly the same as in the solution shown by @ikleyn.
Consider the least common multiple of the given times. The LCM of 6, 15, and 20 is 60.
Now see what each worker or combination of workers could do in 60 hours.
Together the three of them in 60 hours could paint 60/6=10 houses.
Vernon working alone in 60 hours could paint 60/15 = 4 houses.
Dino working alone in 60 hours could paint 60/20 = 3 houses.
That means Joshua alone in 60 hours could paint 10-4-3 = 3 houses.
So Joshua working alone could paint the one house in 60/3 = 20 hours.