SOLUTION: Given that z_1 =
4[cos (pi/3) + i sin (pi/3)] and z_2 = 2[cos (5pi/6) + i sin (5pi/6)]
are complex numbers, find z_2 - z_1. I have to write them in rectangular form, and I don't
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-> SOLUTION: Given that z_1 =
4[cos (pi/3) + i sin (pi/3)] and z_2 = 2[cos (5pi/6) + i sin (5pi/6)]
are complex numbers, find z_2 - z_1. I have to write them in rectangular form, and I don't
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Question 1053020: Given that z_1 =
4[cos (pi/3) + i sin (pi/3)] and z_2 = 2[cos (5pi/6) + i sin (5pi/6)]
are complex numbers, find z_2 - z_1. I have to write them in rectangular form, and I don't know how. Answer by ikleyn(52781) (Show Source):
You can put this solution on YOUR website! .
Given that z_1 =
4[cos (pi/3) + i sin (pi/3)] and z_2 = 2[cos (5pi/6) + i sin (5pi/6)]
are complex numbers, find z_2 - z_1. I have to write them in rectangular form, and I don't know how.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
z = 4(cos (pi/3) + i sin (pi/3)).
You probably know that cos(pi/3) = and sin(pi/3) = .
Substitute it in the formula for z. You will get
z = = .
That's all with this case.
For the other z do the same (or similar).
Use cos(5pi/6) = and sin(5pi/6) = .
